input:
a = number to be squared
x = estimated result (can be any numberm but the better estimation the better
result)

output:
x = close to sqrt(a)

algorithm: execute this code as many times you need. usually 4-6 iterations give
enough precision.
x = (x + a/x)/2;

for fixed point you need to take care of division (choose on depending what
range/precision you want):

x = (x + a/(x>>10))>>1;
x = (x + (a<<5)/(x>>5))>>1;
x = (x + (a<<10)/x)>>1;


--
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